Question

a plane travels a distance of 1200 km at a certain speed. But on the return trip its speed was increased by 80 km/h and hence it took 30 mins less than the onward journey. Find the original speed​

Answer 1

Let the original speed be x km/ hr
Time taken = 1200
_____hr
X
Return speed =x +80km/hr
Time taken = 1200/x+80 - hrs

By Gavin condition
1200/x - 1200/x+80 = 30/60

Solving we get x = 400 km/hr

Answer 2

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