Question

A plane travels at a distance of 2400 km at a certain speed. But on return trip due to bad weather, it reduces its speed by 50 km/h and covers the same distance in 12 minutes more than that of onward journey .Find the original speed of the plane.

Answer 1

Answer:

800 km/h

Step-by-step explanation:

Answer 2

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$\frac{2400}{x - 50} - \frac{2400}{x} = 12 \: minute$

$\rightarrow \: \frac{x - (x - 50)}{x(x - 50)} = \cancel{ \frac{12}{2400} } \times \frac{1}{60}$

$\rightarrow \: \: \frac{50}{x(x - 50)} = \frac{1}{2000} \times \frac{1}{60}$

$\rightarrow \: {x}^{2} - 50x = 10000 \times 60$

$\rightarrow \: \: {x}^{2} - 800x + 750x - 600000$

$\rightarrow \: \: x(x - 800) + 750(x - 800) = 0$

$\rightarrow \: \: (x - 800) \: (x + 750) = 0$

$\therefore \: x = 800$