Question

A plane wavefront of light of wavelength 5500a° is incident on two slits in a seven perpendicular to the direction of light rays . If the total separation of 10 bright fringes on a screen 2m away is 2 cm find the distance between slits .​

Answer 1

Explanation:

I hope it will be help full for you thanks

Answer 2

Given:

The wavelength off plane wavefront (λ) = 5500A°

Distance between screen and slits = 2 meters

The length on-screen of 10 bright fringes = 2 cm

To Find:

The distance between the two slits.

Solution:

The width of 10 bright fringes = 2 cm = 20 mm

⇒ The width of one bright fringe = 20/10 mm = 2 mm

And, the fringe width (β) = λD/d

⇒ Distance between the two slits (d) = λD/β

Putting the values in the above expression

⇒ Distance between the two slits (d)= (55 × 10⁻⁸ × 2)/ 2 × 10⁻³ = 55× 10⁻⁵m

Hence, the distance between the two slits is equal to 0.55 mm.