Physics, asked by srivastavakash4270, 8 months ago

A planet has a mass 20% more than that of earth and radius is 20% less than that of earth. then find the acceleration due to gravity.

Answers

Answered by titiksha06
0

Answer:

Force due to gravity at earth's surface on a mass m:

F = GMm/R2

F = Gravitational Force

G = Gravitational Constant

M = Earth's Mass

m = mass of body

R = Earth's radius

The acceleration is F/m:

g = F/m = GM/R2

For a planet with 0.9M and 1.2R:

a = G(0.9M)/(1.2R)2 = 0.625 (GM/R2) = 0.625g (62.5% of Earth's acceleration due to gravity)

Answered by sushmadhkl
0

Answer: The acceleration due to gravity will be 187.5% when the mass becomes 20% more and radius is 20% less than that of earth.

Explanation:

Gravitational force due to gravity at earth's surface on mass m:

F = \frac{GM}{R^{2} }

As we know, force= mass × acceleration

therefore, acceleration =  \frac{F}{m}    

g =  \frac{F}{m} = \frac{GM}{R^{2} }

Mass and radius  after 20% more and 20% lesser Respectively are 1.2 m and 0.8R (Assuming the value of mass and radius as 1)

a = \frac{G(1.2m)}{(0.8R^{2} )}

a = \frac{1.2}{(0.8)^{2} } (\frac{GM}{R^{2} } )

a = 1.875 (\frac{GM}{R^{2} })

187.5% of earth's acceleration due to gravity.

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