Question

A planet has mass 6.4 x 10²⁴ kg and radius 3.4× 10 ⁶m.
Calculate energy required to
remove an object of mass 800 kg from the surface of the planet to infinity.
​

Answer 1

Answer:

Energy required to remove the object from the surface of the planet is 1.004 × 1011 J

Answer 2

Answer:

Given: M = 6.4 × 1024 kg, R = 3.4 × 106 m, m = 800 kg

To find: Energy required to remove the object from the surface of planet to infinity = B.E.

Formula: B.E. =

GMm

R

GMmR

Calculation: We know that,

G = 6.67 × 10–11 N m2/kg2

From formula,

B.E. =

6.67×10-11×6.4×1024×8003.4×106

∴ B.E. =

6.67×6.4×83.4×109

=6.67×51.23.4×109

= antilog{log(6.67) + log(51.2) – log(3.4)} × 109

= antilog{0.8241 + 1.7093 – 0.5315} × 109

= antilog{2.0019} × 109

= 1.004 × 102 × 109

= 1.004 × 1011 J

Energy required to remove the object from the surface of the planet is 1.004 × 1011 J.