Physics, asked by MiniDoraemon, 6 months ago

A planet in a distant solar system is 10times more massive than the earth and its radius is 10 times smaller .Given that the escape velocity from the earth is 11km/s, the escape velocity from the surface of the planet would be [AIEEE 2008]​

Answers

Answered by zakiralitreader
0

Answer:

please follow me

Explanation:

Explanation: It is given that, A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. So, the escape velocity from the surface of the planet would be 110 km/s

Answered by TheLifeRacer
2

Explanation:- let the mass of earth is m and so mass of of planet m' = 10m

and Radius of earth is R so radius of planet R' = R/10

∴ As we know that from earth escape velocity V= √GM/R = 11_____(i)

for planet escape velocity v' = √2GM'/R'

  • V' = √2G× 10M /R/10 = √100×2GM/R

  • ⟹ √100 × 11 _______ From (I)

⟹ 10* 11 = 110km/s Answer

Similar questions