A planet is rotating around a star in a circular orbit with time period T. the kinetic energy of the planet will be proportional to?
Answers
Answered by
5
Answer:
Time=distance /speed
Answered by
2
Explanation:
ANSWER
According to the question, the gravitational force between the planet and the star is F∝
R
5/2
1
∴F=
R
5/2
GMm
Where M and M be masses of star and planet respectively.
For motion of planet in circular orbit,
mRω
2
=
R
5/2
GMm
mR(
T
2π
)
2
=
R
5/2
GMm
(∴ω=
T
2π
)
T
2
4π
2
=
R
7/2
GM
⇒T
2
=
GM
4π
2
R
7/2
T
2
∝R
7/2
or T
2
∝R
7/4
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