Question

A planet moving around sun sweeps area a1 in 2 days a2 in 3 days and a3 in 6 days. Then the relation between a1 ,a2 and a3 is

Answer 1

according to Kepler’s Law of Areas – The line joining a planet to the Sun sweeps out equal areas in equal interval of time.

given, The planet moving around the sun sweeps area a1 in 2 days , a2 in 3 days and a3 in 6 days .

e.g., a1/2 = a2/3 = a3/6

or, 3a1/6 = 2a2/6 = a3/6

or, 3a1 = 2a2 = a3

hence, relation between a1, a2 and a3 is , 3a1 = 2a2 = a3

Answer 2

Answer:

3A1=2A2=6A3

Step-by-step explanation:

Solve it by using keplers 2 law

i. e. Laws of planetary motion