Question

a planet moving in a circular orbit it ompletes 2 revolutions in 360days then finds its angular frequency

Answer 1

Explanation:

Given : T=5.26×10

3

s, a=9.32m/s

2

Centripetal acceleration a=

r

v

2

=9.32

or v

2

=9.32r

or v=

9.32(R

e

+h)

Time period of revolution is given by T=

v

2π(R

e

+h)

=

9.32(R

e

+h)

2π(R

e

+h)

or T=

9.32

2π

R

e

+h

∴ 5.26×10

3

=

3.05

2×3.14

R

e

+h

R

e

+h

=2.55×10

3

R

e

+h=6.53×10

6

h=6.53×10

6

−6.37×10

6

(∵R

e

=6.37×10

6

m)

h=0.16×10

6

m

h=160×10

3

m=160km

please mark it as brain list answer