Question

A planet of mass 3 × 1026 kg moves around a star with a constant speed of 2 × 106 ms1 in
a circle of radius 1.5 × 1012 m. The gravitational force acting on the planet is​

Answer 1

Explanation:

The force would be the centripetal force.

F = mv^2/r

where m is the mass of the planet

v is the velocity of it

r is the radius it is making.

F = 3*10^26*4*10^32/(1.5*10^12) = 8*10^46 N

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#ANSWER WITH QUALITY....

Answer 2

Gravitational force supplies centripetal force
∵F=
r
mv
2

​
=
1.5×10
14

3×10
29
×(2×10
8
)
2

​
dynes
=8×10
31
dyne =8×10
26
N(∵1N=10
5
dyne. )