A planet of mass m is revolving around the sun
in a circle of radius r. What is the work done by
the gravitational force F in moving the planet
over half the circumference of the circle?
Answers
Answered by
2
Explanation:
Work done is equal to zero assuming earth revolves around the sun in a perfect circle.
As Work=Force∗Displacement∗cosθ
Where θ is the angle between force and displacement .
In this case θ=90degree
As centripetal force is involved where earth is pulled towards the sun and direction of motion at each point is tangential to the orbit and as tangent makes 90degree with radius θ=90degree
Cos90
o
=0
Thereby F∗S∗cos90=F∗S∗0=0
HENCE NO WORK IS DONE .
verified_toppr
Answer verified by Toppr
View
2587 Views
Answered by
3
Explanation:
it's your answer bro I hope help you have a great day take care of yourself
Attachments:
Similar questions