A planet of mass m is revolving around the sun in elliptical orbit of semi major axis x and semi minor axis y. The areal velocity of an elliptical revolution is
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Given the perihelion = r2 = shortest distance of a planet from Sun
aphelion = r1 = longest distance of planet from Sun
mass of planet = m.
mass of Sun = M
So the length of the major axis of the Elliptical orbit of the planet
= r1 + r2.
Semimajor axis = R = (r1 + r2)/2.
According to Kepler's laws:
The square of time period T of a planet revolving around Sun is proportional to the cube of semi major axis R of the elliptical orbit of the planet.
T² ∞ R³
T ∞ R³/²
T ∞ [r1 + r2] ³/² Answer.
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