Question

A planet of mass m moves around sun of mass M in an elliptical orbit. the max and min dist. Of the planet from the sun are r1 and r2 respectively.The time period of the planet is proportional to?

Answer 1

PLEASE MARK BRAINLIEST....

Answer:

Given the perihelion = r2 = shortest distance of a planet from Sun

                 aphelion = r1 = longest distance of planet from Sun

                 mass of planet = m.

                 mass of Sun = M

So the length of the major axis of the Elliptical orbit of the planet

    = r1 + r2.

Semimajor axis = R = (r1 + r2)/2.

According to Kepler's laws:

    The square of time period T of a planet revolving around Sun is proportional to the cube of semi major axis R of the elliptical orbit of the planet.

    T² ∞ R³

    T ∞  R³/²

    T  ∞ [r1 + r2] ³/²     Answer.

Answer 2

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