Physics, asked by keertikantis, 1 year ago

A planet of mass m moves round the sun of mass M in a circular orbit of radius r with angular speed omega. Another planet of mass 2m moves round the sun in circular orbit of radius 4rwith angular speed omega'. Find the ratio of omega / omega'.

Answers

Answered by abhi178
98
here gravitational force between planet and sun is balanced by centripetal force.

case 1 : mass of planet = m, mass of sun = M, radius of circular orbit = r and angular speed is \omega

then, \frac{GMm}{r^2}=m\omega^2r

or, \omega^2=\frac{GM}{r^3}......(1)

case 2 : mass of planet = 2m

radius of circular orbit = 4r

and angular speed = \omega

then, \omega'^2=\frac{GM}{(4r)^3}

or, \omega'^2=\frac{1}{64}\frac{GM}{r^3}......(2)

from equations (1) and (2),

\frac{\omega^2}{\omega'^2}=\frac{64}{1}

\frac{\omega}{\omega'}=8
Answered by bharathjeeva2002
3

Answer:

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