Question

A planet revolves around sum whose mean distance is 1.588 times the mean distance between earth and sun. The revolution time of planet will be

Answer 1

Answer:

Hey mate here is your answer.//

Explanation:

T²∝r³,

T²/r³=K,

Te²/re³=Tp²/(re)³,

rp=1.588re,

Te²/(re)³=Tp²/(1.588)³×re³,

Tp²=Te²×(1.588)³,

Tp=Te×(1.588)3/2 root,

so,Tp=2Te.

Te=1 year,

so,2Te=2(1)

=2 years is the revolution time of the planet.//

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