Physics, asked by salimnafisa9, 17 days ago

A planet x has a mass 3 times and radius 6 times that of the Earth. What is the acceleration due to gravity on the planet, if the acceleration due to gravity on the Earth is 10 m/s2.​

Answers

Answered by ragadeepthianil
1

Answer:

Answer:-

0.83 m/s²

Explanation:-

We know that :-

gₑ = GMₑ/R²ₑ

Where :-

• gₑ is the acceleration due to gravity on

the earth's surface.

• G is Universal Gravitational Constant.

• Mₑ is mass of the earth.

• Rₑ is radius of the earth.

_____________________________

∴ 10 = GMₑ/R²ₑ ----(1)

Now according to the question, mass of planet 'X' is 2 times that of earth and radius of the planet is 3 times that of earth.

∴ Mₚ = 3Mₑ

∴ Rₚ = 6Rₑ

Hence, expression for acceleartion due to gravity on planet 'X' (gₚ) will be :-

=> gₚ = GMₚ/R²ₚ

=> gₚ = G×3Mₑ/(6Rₑ)²

∴ gₚ = 3GMₑ/36R²ₑ ----(2)

On dividing eq.2 by eq.1, we get :-

=> gₚ/10 = [3GMₑ/36R²ₑ]/[GMₑ/R²ₑ]

=> gₚ/10 = 3/36

=> gₚ = 3×10/36

=> gₚ = 0.83m/s²

Thus, acceleration due to gravity on the planet 'X' is 0.83m

Explanation:

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