Physics, asked by Hushvanth, 4 months ago

A planets revolves around the sun with the speed 40 Km/s. its period of revolution around the sun is 40,000 sec, its centripetal acceleration will be​

Answers

Answered by sahilrajsoni990
0

Answer:

=3×10

4

m/s

Time of revolution = One year = 356 days (convert into seconds)

=365×24×60×60=3.5×10

7

seconds

The formula of radial acceleration:

a

c

=V

2

/r

Distance covered by the earth around the sun will be equal to the circumference of orbit.

Speed × Time ( V.T ) = 2πr

r = V.T/2π

a

c

=V

2

/r=V

2

×2π/V×T

a

c

=2πV/T

a

c

=

3.5×10

7

2×3.14×3×10

4

$$ a_c = 5.98 ×10 ^{-3}m/s^2

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