Physics, asked by digvijaykoppanathi, 9 months ago


A plank of area of cross section A and
mass n is half immersed in liquid
I of density p and half in rigid 2
of densory ap , what is period of
collision Oscillarion of plank if it
is slightly de pressed downwards
1-2 Р​

Answers

Answered by PoojaBurra
0

Given :

Area of cross-section of plank = A

Mass of the plank = m

Density of the liquid 1 = ρ

Density of the liquid 2 = 2ρ

To Find :

The time period of the oscillation of the plank

Solution :

  • The Buoyancy force acts on the block if it is given a downward displacement
  • Buoyancy force = -2xAg-(-xAg)

                              = -xAg

  • This buoyancy force acts as restoring force

         ma = -Agx

         a = \frac{-Agx}{m}

         a = -\omega ^{2} x

  • As it is clear that the accelartion of a particle is proportional to its displacement the motion is SHM
  • Time period of the particle = T = \frac{2}{\omega}

                                                        T = \frac{2m}{Ag}

The time period of oscillation of the plank is (2m/Ag) sec

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