A plank with a box on it at one end is gradually raised about the other end. As the angle of
inclination with the horizontal reaches 30° , the box starts to slip and slides 4.0 m down the
plank in 4.0 s. The coefficients of static and kinetic friction between the box and the plank will
be, respectively ?
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Static coefficient of friction is μs=tan30o=0.577≈0.6
For kinetic friction, ma=mgsin30−f=mgsin30−μkmgcos30
a=gsin30−μkgcos30....(1)
and also using S=ut+1/2at2,
⇒4=0+(1/2)a(4)2
or a=0.5m/s2
Now from (1) we get, 0.5=10(1/2)−μk(10)(23)
or μk=534.5=0.5
refer to this related ans.
it may help to understand ♡
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