Question

A plano convex lens of focal length 100cm
has convexe surface of radius of curvature 60 cm
The refractive index of the lens is​

Answer 1

Answer:

1.6

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Answer 2

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It is given that :-

• Focal length of lens = 100cm.
• Radius of curvature of surface = 60cm.

Now, we know that the lens formula is :

$\frac{1}{f} = (\mu - 1)\frac{1}{r} + \frac{?}{r_2}$

After inputting tue values we get :-

$\frac{1}{100} = (\mu - 1) \times \frac{1}{60} + \frac{1}{60}$

$\frac{1}{100} = \frac{\mu - 1}{30}$

$30 = 100\mu - 100$

$130 = 1 00\mu$

$\mu = \frac{130}{100} = \cancel \frac{130}{100} = 1 .3$

Therefore we get that refractive Index of given lens is 1.3.

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BY SCIVIBHANSHU

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