Physics, asked by ggg23, 1 year ago

A plano-convex lens of radius 1.0 m is placed on an optically flat glass plate and is

illuminated by an extended monochromatic source. Assume that the point of contact

is perfect. The diameters of the 10th and 5th dark rings in the reflected light are

4.50 × 10−3m and 3.36 × 10−3m. Next, the space between the lens and the glass plate

is filled with a liquid. The diameter of the 5th ring changes to 3.0×10−3m. Calculate

the refractive index of the liquid when the ring is (i) dark, and (ii) bright, if the

wavelength of light is 589 nm.

Answers

Answered by priyanka05
1

convex lens of radius 1.0 m is placed on an optically flat glass plate and is illuminated by an

extended monochromatic source. Assume

that the point of contact is perfect. The diameters of the

10th and 5th dark rings in the reflected light are 4.50 × 10−3m and 3.36 × 10−3m. Next, the space

between the lens and the glass plate is filled with a liquid. The diameter of the 5th ring changes

to

3.0×10−3m. Calculate the refractive index of the liquid when the ring is (i) dark, and (ii) bright, if the

wavelength of light is 589 nm.

Find:

n

dark

-

? n

bright

-

?

Given:

R=1.0 m

r

5

=

1

.

5

×10

3

m

λ=589×10

-

9

m

Solution:

For

dark

ring

:

r

5

=

kR

λ

n

(1), where k=5

Of (1)

Þ

n

=

kR

λ

r

5

2

(2)

Of (2)

Þ

n=1.3089

For

bright

ring

:

r

5

=

(

2k

1

)

R

λ

2n

(3), where k=5

Of (3)

Þ

n

=

(

2k

1

)

R

λ

2

r

5

2

(4)

Of (4)

Þ

n=1.178

0

Answer:

(i)

1.3089

(ii)

1.178

 


priyanka05: sry
Similar questions