Question

a plano convex lens of radius of curvature 0.1m is kept over a plane glass plate with curved surface of the lens touching it. the gap between the glass plate and curved surface of lens is filled with a liquid. if the combined focal length of the combination is 0.4m. calculate the refractive index of material of the liquid. given refractive index of the material of lens is 1.5​

Answer 1

Answer:

Explanation:

The combination is used to view an object of 5 cm length kept at 20 cm from the ... If in a plano-convex lens, the radius of curvature of the convex surface is 10 ... When the lens is placed in liquid of refractive index 4/3 , its focal length will be ... A glass lens is placed in a medium in which it is found to behave like a glass plate.

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Answer 2

Explanation:

Given a plano convex lens of radius of curvature 0.1 m is kept over a plane glass plate with curved surface of the lens touching it. the gap between the glass plate and curved surface of lens is filled with a liquid. if the combined focal length of the combination is 0.4 m. calculate the refractive index of material of the liquid. given refractive index of the material of lens is 1.5

• Now for the plano convex lens
• Radius of curvature R = 0.1 m
• Refractive index μ1 = 1.5
• Now we have the lens maker formula 1/f = (μ – 1) x (1/R1 – 1/R2)  
• where f is focal length of lens, μ is the refractive index, R1 and R2 are radius of curvature of both surfaces)
•            So 1/f1 = (μ1 – 1) (1/R1 – 1/R2)
•                         = (1.5 – 1) (1/0.1 – 1/ꝏ)
•                          = 0.5 / 0.1
•                            = 5
•                  1/f1 = 5 m
• Now  the combined focal length of the combination F = 0.4 m
• So we get 1/F = 1/f1 + 1/f2
•                  1/0.4 = 1/0.2 + 1/f2
•                   1/f2 = 1/0.4 – 1/0.2
•                          = 10 / 4 – 10 / 2
•                         = 10 – 20 / 4
•                          = - 10 / 4
•                      1/f2  = - 5/2 m
• So now curved surface lens is filled with liquid
•                 1/f2 = (μ2 – 1) (1/R1 – 1/R2)
•                  -5/2 = (μ2 – 1) (1/ꝏ – 1/0.1)  
•                     -5/2 = (μ2 – 1) (- 1/0.1)
•                       -5/2 = - 10 (μ2 – 1)
•                       μ2 – 1 = 1/4
•                        Or μ2 = 1/4 + 1
•                                  = 5/4
•                        Or μ2 = 1.25
• So refractive index of material of the liquid is 1.25

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https://brainly.in/question/5189319