A plastic ball falling from a height 4.9 m rebounds number of times. If total time for second collision is 2.4 sec, then coefficient of restitution is 1) 0.3 2) 0.4 3) 0.7 4) 0.6
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If total time for second collision is 2.4sec, then coefficient of restitution is. Solution : T=t+2t1=√2hg[1+2e] since tn=en′t.
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