Question

A plastic box 1.5 m long 1.25 m wide and 65 cm deep is to be made it is opened at the top ignoring the thicknss of plastic determine the area of sheet required for making the box

Answer 1

Answer:

5.45sq.m

Step-by-step explanation:

$l = 1.5m \\ b = 1.25m \\ h = 65cm = \frac{65}{100} m = 0.65m \\ area \: of \: sheet \: required = area \: of \: cuboid \: - area \: of \: top \: which \: is \: open \\ = 2(lb + bh + lh) - lb \\ = 2lb + 2bh + 2lh - lb \\ = lb + 2bh + 2lh \\ = (1.5 \times 1.25) + 2(1.25 \times 0.65) + 2(1.5 \times 0.65) \\ = 1.875 + 1.625 + 1.95 \\ = 5.45 {m}^{2}$

Answer 2

Question :-

A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is to be made. It is opened at the top. Ignoring the thickness of the plastic sheet, determine

(i) The area of the sheet required for making the box.

(ii) The cost of sheet for it, if a sheet measuring 1m2 costs ₹20.

Answer :-

(i) Here, length (l) = 1.5 m, bread th(b) = 1 .25 m

and height (h) = 65 cm = 65/100 m = 0.65 m

∵ It is open from the top.

∴ Its surface area

= [Lateral surface area] + [Base area]

= [2(1 + b)h] + [lb]

= [2(1.50 + 1.25)0.65] m2 + [1.50 x 1.25] m2

= [2 x 2.75 x 0.65] m2 + [1.875] m2

= 3.575 m2+ 1.875 m2 = 5.45 m2

∴ Area of the sheet required for making the box = 5.45 m2

(ii) Cost of 1 m2 sheet = Rs. 20

Cost of 5.45 m2 sheet = Rs. (20 x 5.45)

= Rs. 109

Hence, cost of the required sheet = Rs. 109

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