Question

A plastic box 1.5 m long, 1.25 m wide and 65 cm deep, is to be made. It is to be open at the top. Ignoring the thickness of the plastic sheet, determine: (i)The area of the sheet required for making the box. (ii)The cost of sheet for it, if a sheet measuring 1m2 costs Rs. 20.

Answer 1

Answer:

Rs. 109

Step-by-step explanation:

Length of box =1.5 m, Breadth =1.25 m, Height =0.65 m

⇒Area to be white-washed = Area of cuboid − Area of base.

(i) Area of sheet requred =2lb+2bh+2lh−lb

(i) Area of sheet requred =2lh+2bh+lb ..[Boxisopen]

=[2×1.5×0.65+2×1.25×0.65+1.5×1.25] m2

=(1.95+1.625+1.875)m2 =5.45 m 2

ii) Cost of sheet per m

2area = Rs. 20

Cost of sheet of 5.45m 2area = Rs. 5.45×2 = Rs. 109

Answer 2

$\bold\pink{Given:}$

$\sf\color{navy}{length\: (l) \:of \:box = 1.5m}$

$\sf\color{navy}{Breadth \:(b) \:of\: box = 1.25 m}$

$\sf\color{navy}{=Depth\: (h)\: of\: box = 0.65m}$

$\bold\pink{To\: find}$

$\sf\color{navy}{(i)\:The\: area \:of \:the \:sheet \:required\: for\: making\: the \:box }$

$\sf\color{navy}{(ii)The\: cost\: of\: sheet\: for \:it, \:if\: a\: sheet \:measuring\: 1m^2\: costs\: ₹ 20}$

$\bold\pink{Solution}$

$\sf{Box\: is \:to\: be\: open\: at\: top}$

$\sf{Area \:of \:sheet \:required.}$

$\sf{= 2lh+2bh+lb}$

$\sf{= [2×1.5×0.65+2×1.25×0.65+1.5×1.25]m^2}$

$\sf{= (1.95+1.625+1.875) m^2 = 5.45 m^2}$

$\sf\color{navy}{Now,}$

$\sf{Cost\: of\: sheet\: per\: m^2\: area = ₹20}$

$\sf{Cost \:of \:sheet\: of\: 5.45\: m^2 \:area = ₹ (5.45×20)}$

$\sf{= ₹109}$