Question

.A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is to be made. It is opened at the top. Ignoring the thickness of the plastic sheet, determine
(i) The area of the sheet required for making the box.
(ii) The cost of sheet for it, if a sheet measuring 1m2 costs ₹20.​

Answer 1

Answer:

Given:

Length of box =1.5 m, Breadth =1.25 m, Height =0.65 m

⇒Area to be white-washed = Area of cuboid − Area of base.

(i) Area of sheet requíred =2lb+2bh+2lh−lb

(i) Area of sheet requíred =2lh+2bh+lb [Box is open]

=[2×1.5×0.65+2×1.25×0.65+1.5×1.25] m²

=(1.95+1.625+1.875)m²

=5.45 m²

ii) Cσst of sheet per m²

area = Rupєєѕ 20

C ost of sheet of 5.45m²

area = Rs. 5.45×20

= Rs. 109

Step-by-step explanation:

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αur вtαíчє єхαm kєѕα gчα

Answer 2

Question:-

A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is to be made. It is opened at the top. Ignoring the thickness of the plastic sheet, determine

(i) The area of the sheet required for making the box. (Answer : 5.45m²)

(ii) The cost of sheet for it, if a sheet measuring 1m2 costs ₹20.

(Answer : ₹109)

(i) The area of the sheet required for making the box.

Solution:

Given:

• Length of box = 1.5 m

• Breadth = 1.25 m

• Depth = 65 cm

Conversion : (cm - m)

65 cm = $\frac{65}{100}m$

ㅤㅤㅤ= 0.65 m

Now calculating Area of sheet required for making box:

Area of sheet required:

• Area of cuboid - Area of top which is open

Area of cuboid = 2(lb + bh + lh)

ㅤㅤㅤㅤㅤ= 2(lb + bh + lh) - lb

ㅤㅤㅤㅤㅤ= 2(lb) + 2(bh) + 2(1h) - lb

ㅤㅤㅤㅤㅤ= lb + 2(bh) + 2(lh)

Area of top:

• l x b

ㅤㅤㅤ= (1.5 x 1.25) + 2(1.25 x 0.65) + 2(1.5 x 0.65)m²

ㅤㅤㅤ= (1.95 + 1.625 + 1.875) m²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 5.45 m²

(ii) The cost of sheet for it, if a sheet measuring 1 m² costs Rs 20.

Solution:

Area of sheet required:

ㅤㅤㅤㅤㅤㅤㅤ= 5.45 m²

Cost of sheet per 1 m² area:

ㅤㅤㅤㅤㅤㅤㅤ= ₹20

Cost of sheet of 5.45 m² area:

ㅤㅤㅤㅤㅤㅤㅤ= ₹ (5.45 x 20)

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ= ₹109

Hope it helps ya!

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