A plate of dimensions (4m * 4m) and 0.01 m away from a fixed plate moves at 4 m per sec ¹. A force of 1 N is required to maintain this speed. Determine the coefficient of viscosity of the fluid between the plates.
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Answer:
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Answer:
dy=0.025mm
=0.025×10
−3
m
Velocity of upper plate .
=60cm/s=0.6m/s
Force on upper plate
=2
m
2
N
= Shear stress , τ
du = change of velocity =u–0=0.6m/s
dy = change of distance =0.025×10−3m
Viscosity,
μ=
du/dy
τ
=
(0.6/0.25×10
−3
)
2
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