Question

A plate of mass100gm is kept floating horizontally in air by bullet which are fired with the same velocity at the rate of 10bullets per second . if the mass of each bullets is 5 gram and if the bullets rebounds in opposite direction with same speed then calculate the velocity of each bullet at the time of impact

Answer 1

The mass of plate is M = 100 g = 0.1 kg

The mass of bullet is m = 5 g = 0.005 kg

The bullets are fired at a rate of 10 bullets per second.

Let v be the speed of each bullet.

After colliding with the plate, they rebound with same speed.

Thus, rate of change in momentum of the bullets, that is, the force exerted by bullets is

2 v × 0.005 × 10

This balances the weight of the plate.

2 v × 0.005 × 10 = 0.1 × 9.8

v = 9.8 m/s

Answer 2

Answer:

Please refer to the above attachment.

Thank you.