A plate of thickness t made of a material of refractive index µ is placed in front of one of the slits in a double slit experiment. (a) Find the change in the optical path due to introduction of the plate. (b) What should be the minimum thickness t which will make the intensity at the centre of the fringe pattern zero? Wavelength of the light used is λ. Neglect any absorption of light in the plate.
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Answered by
14
Given :
thickness of plate= t
refractive index of plate =µ
a)Find the change in the optical path due to introduction of the plate:
optical path difference = (µ-1) t
b)For zero intensity at the centre of the fringe pattern, there should be distractive interference at the centre.
So, the optical path difference should be = λ/2
(µ-1) t=λ/2
t= λ/2(μ-1)
∴ the minimum thickness t which will make the intensity at the centre of the fringe pattern zero is t= λ/2(μ-1)
Answered by
4
Explanation:
2(μ−1)/λ
path difference is (μ−1)t
for the intendity to be zero
(μ−1)t=(n+ 21 ) 2/λ
for minimum thickness n=0t= 2(μ−1)λ
option C is correct
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