Question

A platform is 15 m long and 8 m wide. A square carpet with sides 3.8 m is
laid on it. What is the area of the platform not covered with the carpet ?​

Answer 1

Answer:

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Answer 2

Answer:

$\red\bigstar$ Area of platform not covered by the carpet = 105.56 m².

Platform

The platform is in the shape of a rectangle.

Length of the platform = 15m.

Breadth of the platform = 8m.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 15m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 8m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Area of a rectangle = l × b , Where l is the length and b is the breadth of the rectangle.

Here,

l = 15m.

b = 8m.

⇒ Area of the rectangular platform = 15 × 8

⇒ Area of the rectangular platform = 120 m².

Carpet

The carpet is in the shape of a square.

Sides of the carpet = 3.8m.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large 3.8m}\put(4.4,2){\bf\large 3.8m}\end{picture}$

Area of a square = a² , Where a is the side of the square.

Here,

a = 3.8m.

⇒ Area of the carpet = (3.8)²

⇒ Area of the square carpet = 14.44 m².

$\boxed{\sf Area \: of \: the \: platform \: not \: covered \:with \:the \: carpet = Area \:of \: the \:platform - Area \: of \:the \: carpet}$

⇒ Area of the platform not covered with the carpet = (120 - 14.44) m².

⇒ Area of the platform not covered with the carpet = 105.56 m².