Question

A platform is pulled with horizontal acceleration a. A particle is
projected from the platform at an angle with the horizontal
with respect to the platform as shown in figure. The value of
tano such that particle again come to the starting point on the
platform is
(a = 5 m s-2 and g = 10 m s-2)
0

Answer 1

Answer:

therefore to find the starting point tan theta value is need

Explanation:

Equation formula y =(tan θ0)x – gx2/2(v0cosθ0)2