Question

A platform with dimensions 22 m x 14 m x 2.5 m is formed from the earth
digging the well with diameter 7 m. Find the depth of the well.​

Answer 1

$\underline {\huge {\blue {Solution:}}}$

$\bf {GIVEN:}$

Diameter of the well = 7 m

Radius of the well = 7/2 m

Depth of the well = 20 m

Volume of the mud dug from the well = πr^2h

= 22/7 × 7/2 × 7/2 × 20

= 770 m3

Area of the rectangular plot where the mud is spread = 22 x 14

Let the height of the plotfarm be h metres.

Volume of the plot form = Volume of the mud taken from the well

22 x 14 x h = 770

h = 770 / 22x14

$\boxed {h = 2.5 m}$

$\mathfrak{THANK \; YOU}$

Answer 2

Step-by-step explanation:

ANSWER

The shape of the well will be cylindrical as shown in the figure below:

Given:

Depth (h) of well =20 m

Radius (r) of circular end of well =

2

7

m

Area of platform = Length x Breadth =22×14m

2

Assume height of the platform =H

The volume of soil dug from the well will be equal to the volume of soil scattered on the platform.

Volume of soil from well = Volume of soil used to make such platform

⟹πr

2

h = Area of platform x Height of platform

⟹π×( 27 )

2 ×20=22×14×H

H= 7

22 × 4

49 × 22×14

20H= 25

=2.5m

Hence, the height of such a platform will be 2.5 m.