Math, asked by hemashankareagl7270, 1 year ago

A play ground is in the shape of rectangle. The length of rectanglr is three times its breadth and its area is 1728 sq.mts. find the perimeter of the rectangle.

Answers

Answered by IAMHELPINGYOU
1
let, the length of the ground=3x
and the breadth of the ground=x

Area of the ground= length × breadth
=>1728 m²= 3x × x
=>1728 m²= 3x²
=>1728/3 = x²
=>576 = x²
=> √576 = x
=> x= 24

therefore, length=3x= 3×24=72m
and breadth=x = 24m

ronilrocky: HI
ronilrocky: Hlo
Answered by Rajusingh45
3
 \huge \green{Hello \: Friends}

 \underline \bold{Given}

 \bf{length \: of \: ground \: is \: 3 \: times\: the \: breadth}

 \bold{Area \: of \: ground \: is \: 1728 \: sq.m}

 \boxed{Answer = > }

 \bold{Let \: the \: length \: of \: the \: ground \: be \: x}
 \bf{and \: breadth \: be \: y}

 \red{According \: to \: question \: ...}

 \bold{x = 3y}

 \blue{We \: know \: that...}

 \bold{Area \: of \: rectagle \: = lenth \: \times \: breadth}
 \bf{ area \: of \: rectangular \: ground \: = l \: \times b}

 \bf{1728 = x \times y}

 \bf{1728 = 3y \times y..........(x = 3y)}

 \bf{1728 = 3y {}^{2} }

 \bf{y {}^{2} = \frac{1728}{3} }

 \bf{y {}^{2} =576 }

 \bf{y \: = \sqrt{576} }

 \boxed{y \: = 24}

 \orange{Therefore \: the \: values \: are}

 \bf{length \: = 3y = 3 \times 24}

 \boxed{length \: = 72m}

 \bf{breadth \: = y \: = 24}

 \boxed{breadth \: = 24 m}

NOW

PERIMETER = 2(L + B)

=> 2(72+24)

=> 2 X 96

=> 192 m

 \huge \frak{Thanks}

 \boxed{Be \: Brainly}

niti13: #well explained
Rajusingh45: Thanks ....J
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