Question

a play ground of a school is rectangular in shape with length 60m and breath 45m. a cemented pathway running all around it of . width 1 m is built on the outside. find the area of pathway​

Answer 1

new length is 60 +2=62 m

new breath is 45+2=47m

new area is 62 × 47 =2914m^2

old breath =45 m

old length =60m

old area =45 × 60=2700 m ^2

area of path=new area -old area

=2914-2700

=214m^2

PLEASE MARK IT AS BRAINLIST

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The area of the Path is 214 sq.m

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

The Length of the Rectangle = 60 m

Breadth of the Rectangle = 45 m

Width of the path = 1 m

To find :

The area of the path

Solution :

Area of the path = Area of bigger Rectangle - Area of smaller Rectangle.

First, find the area of the Rectangular play ground. (Smaller Rectangle)

Area of Rectangle = $\tt{Length \times Breadth}$

$\tt{\implies} \: 60 \times 45$

$\tt{\implies} \: 2700$

Area of the Smaller Rectangle = 2700 sq.m

$\rule{300}{1}$

Area of the bigger Rectangle =

Length = 60 + 1 × 2 = 62

Breadth = 45 + 1 × 2 = 47

$\tt{\implies}\: 62 \times 47$

$\tt{\implies}\: 2914$

Area of the Bigger Rectangle = 3008 sq.m

$\rule{300}{1}$

Area of the Path =

Area of Bigger Rectangle = 3008 sq.m

Area of the Smaller Rectangle = 2700 sq.m

$\tt{\implies} \: 2914 - 2700$

$\tt{\implies} \: 214$

$\therefore$ The area of the Path is 214 sq.m