Question

A play school has chocolates which can supply 50 students for 30 days. For the first ten days only 20 students were present. How many more students can be accommodated into the earlier group such that the entire chocolates get consumed in 30 days. Assume each student takes the same number of chocolates

Answer 1

Answer: Number of more students can be accommodated in the earlier group is given by $65-20=45$

Step-by-step explanation:

Since we have given that

Number of students to be supplied = 50

Number of days = 30

So, we need to find the more number of students can be accommodated into the earlier group such that the entire chocolates get consumed in 30 days.

Number of chocolates in 30 days = $50\times 30=1500$

For the first ten days only 20 students were present,

Number of chocolates used = $20\times 10=200$

Remaining chocolates is given by

$1500-200=1300$

Number of days left = 30 - 10 =20

So, Number of chocolates used for 20 days is given by

$\dfrac{1300}{20}=65$

Number of more students can be accommodated in the earlier group is given by

$65-20=45$