Question

A player caught a cricket ball of mass 0.15 kg moving at a rate of 20 ms-1. If the catching process is completed in 0.1s, the force of the blow exerted by the ball on the hands of the player is

Answer 1

30 NEWTONS

It is given that,

Mass of cricket ball, MASS = 0.15 kg

Initial velocity of the ball, v = 20m/s

Final velocity of the ball, u = 0 m/s

Time taken in the catching process, t = 0.1

MOMENTUM

MOMENTUMFORCE =_____________

MOMENTUMFORCE =_____________ TIME

F= mv / t

F=( 0.15*20)/0.1

THAT IS 30N

F = 30 N

The force exerted by the ball on the hand of the player is equal to 30 N.

Answer 2

Given info : A player caught a cricket ball of mass 0.15 kg moving at a rate of 20 m/s. the catching process is completed in 0.1 sec.

To find : the force exerted by the ball on the hands of the player is ..

solution : mass of cricket ball, m = 0.15 kg

initial velocity of ball, u = 20 m/s

final velocity of ball , v = 0 m/s [ after catching by player, ball becomes rest ]

time taken in the catching process, t = 0.1 sec

we know from Newton's 2nd law of motion,

         force is the rate of change of linear momentum.

⇒ F = $\frac{|mv-mu|}{t}$

= $\frac{|0\times0.15-20\times0.15|}{0.1}$

= 30 N

therefore the force exerted by the ball on the hands of the player is 30 N.