Question

A Player caught a cricket ball of mass 150g moving at a rate of 20m/s . if the catching process is completed in 0.1s the force of the blow exerted by the ball in the hand of the players is equal is to .[AIEEE 2006] ​

Answer 1

Explanation:- This is the question based on impulse momentum theorem .

• |F*∆T| = |change in momentum|
• |F∆T| = |pᶠ - pᵢ |
• As the ball will stop after catching
• pᵢ = mvᵢ = 0.15 × 20 = 3 , pᶠ = 0
• F × 0.1 = 3

=> F = 30N Answer

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Answer 2

Answer:

F = Impulse/Time taken

= 0.15x20/0.1

= 30N.

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