A player hits a ball of mass 0.3 kg which was moving eastward with a velocity of 10 metre per second causing it to move with a velocity of 50 m per second Westwood the force of the blowout on the ball for 0.01 second calculate the average Force exerted by the ball
by the player
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Answer:
Mass =0.03kg
For t=0.01s
acc=10m/s
So, force =m*acc
=0.03*10
=0.3 N
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