Physics, asked by emmanuelleghomorai, 10 months ago

A player hits a ball of mass 0.3 kg which was moving eastward with a velocity of 10 metre per second causing it to move with a velocity of 50 m per second Westwood the force of the blowout on the ball for 0.01 second calculate the average Force exerted by the ball
by the player

Answers

Answered by Ambarsariya
2

Answer:

Mass =0.03kg

For t=0.01s

acc=10m/s

So, force =m*acc

=0.03*10

=0.3 N

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