A player hits a ball towards a net of height 5 m with a speed of 20 m/s. The ball
just rises up to the top of the net and falls inside it.
Find the horizontal distance this ball would have travelled had there been no net in
its way. (Take g = 10 m/s2)
Answers
Given : A player hits a ball towards a net of height 5 m with a speed of 20 m/s. The ball just rises up to the top of the net and falls inside it.
(Take g = 10 m/s2)
To Find : the horizontal distance this ball would have travelled had there been no net in its way.
Solution:
speed of 20 m/s
angle = α
Vertical speed = 20sinα
just rises up to the top of the net
=> Vertical speed = 0
=> t = 20sinα/g
V² - U² = 2aS
=> (20sinα)² = 2 g(5)
=> sin²α = g/40
g = 10
=> sin²α = 1/4
=> sin α = 1/2
=> α = 30°
t = 20sinα/g = 20 (1/2)/10 = 1 sec
Horizontal Speed = 20cosα = 20(√3/2) =10√3
Horizontal distance = 2 * 10√3 * 1 = 20√3
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