A player is rolling a die. In the first three throws, he
gets a 6 each time. What is the probability that he will
get a 6 in the fourth throw?
Answers
Answered by
0
Answer:
1/6
Step-by-step explanation:
Answered by
5
Answer:
as p(event)=favorable cases /total cases so
p(getting 6 )=3/3=1
so it is a sure event
it is the answer by experimental probability
but according to practical probability ans=1/6
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