A player kick a 0.5 kg football and gives it a velocity of 10m/s.from rest.The contact between them lasts for 1/50sec.what is the force of impact?
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Answered by
42
f = ma
f= m × v-u/t
f = 0.5 × 10/1÷50
= 0.5 × 500
= 250.0 N
Hope this helps
f= m × v-u/t
f = 0.5 × 10/1÷50
= 0.5 × 500
= 250.0 N
Hope this helps
Gokul0Indhalur:
s rest is 0 velocity
sry v-u is right . typed wrongly dude
in which class r u studying
Class 8
nice....u surendar
Answered by
25
initial velocity(u) = 0m/s
final velocity(v)= 10m/s
time= 1/50= 0.02s
final velocity(v)= 10m/s
time= 1/50= 0.02s
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