Physics, asked by geetagupta40270, 9 months ago

a player move along the boundry of square boundry of side 50 m in 200 sec the magnitude of displacement of farmer at the end of 11 min 40 sec from his initial position is​

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Answered by Anonymous
0

Answer:

Square ground of 50 m  sides

=> perimeter = 4 * 50 = 200 m

one round is completed in 200 Sec

=> Hence speed = 1 m/s

Distance Covered in 11 min 40 secs = 700 sec    = 700 m

700 = 200 + 200 + 200 + 100

Hence he has moved 100 m from initial position

50 m on one side  and 50 m at right angle

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