Question

A player moves along the boundary of a square ground of side 50m in 200 sec.the magnitude of displacement of the farmer at the end of 11 minutes 40 seconds from it's initial position.​

Answer 1

Answer:

50√(2)

after 600 sec he will be at the initial position so in next 100 sec he will cover 2 sides of the square and now he is at diagonally opposite point to initial position

so displacement =√((50)^2+(50)^2)

|| =50√2

Answer 2

Answer:

50root2 is answer

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