Question

A player moves along the boundary of a square ground of side 50 m in 200 sec. The magnitude of displacement of the farmer at the end of 11 minutes 40 seconds from his initial position is

Answer 1

Answer:

A player moves along the boundary of a square ground of side 50m in 200 sec. The magnitude of displacement of the farmer at the end of 11 min 40 sec from his initial position is A) 50m

Answer 2

Answer:

11 min 40 sec=700 s

in 200 sec= 4×50 m (boundary=perimeter)=200m

so in 700 s he move 700 m

so he make 3 and 1/2 rounds

the displacement will be the length of diagonal as he will be at opposite vertex which we can find by using Pythagoras theorem

$x {}^{2} = 50 {}^{2} + 50 {}^{2}$

$x {}^{2} = 2500 + 2500 = 5000$

$x = \sqrt{5000}$

$x = 50 \sqrt{2}$

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