Question

a player moves along the boundary of a square ground of side 50m in 200sec. the magnitude of the displacement of the farmer at the end of 11mins 40sec from his initial position is:​

Answer 1

Explanation:

Time taken to travel 200m(perimeter of square is 4* side)=200s.i.e. time taken to travel 1m is 1sec.i.e. speed of player is 1m/s so The distance travelled is (1*(11*60)+40)= 700 m i.e.3.5 rounds of the field so displacement is AC [see in photo] =diagonal of square According to pythagoras theorem (AD)^2+(DC)^2=(AC)^2.So

AC=(2500+2500)^1/2.

AC=50 root 2Answer:option D