Question

A player moves along the boundary of a square ground of side 50m in 200 sec.The magnitude of displacement of the farmer at the end of 11 min 40 sec from his initial position is​

Answer 1

Explanation:

Square ground of 50 m sides

=> perimeter = 4 * 50 = 200 m

one round is completed in 200 Sec

=> Hence speed = 1 m/s

Distance Covered in 11 min 40 secs = 700 sec = 700 m

700 = 200 + 200 + 200 + 100

Hence he has moved 100 m from initial position

50 m on one side and 50 m at right angle

Hence Distance of final position from initial position = √50² + 50²

= 50√2

50 √2 m is the displacement of the player at the end of 11 minutes 40 seconds

Answer 2

Answer:

50 √2  m is the displacement of the player at the end of 11  minutes 40 seconds

Explanation:

Square ground of 50 m  sides

=> perimeter = 4 * 50 = 200 m

one round is completed in 200 Sec

=> Hence speed = 1 m/s

Distance Covered in 11 min 40 secs = 700 sec    = 700 m

700 = 200 + 200 + 200 + 100

Hence he has moved 100 m from initial position

50 m on one side  and 50 m at right angle

Hence Distance of final position from initial position =  √50² + 50²

= 50√2

50 √2  m is the displacement of the player at the end of 11  minutes 40 seconds