Question

A player moves along the boundary of a square ground of side 50 m in 200 sec.The magnitude of displacement of the farmer at the end of 11 minutes 40 seconds from his initial position is *


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Answer 1

answer. Explaination:time taken to travel 200m( perimeter of square is 4*side)=200s. i.e time taken to travel 1m is 1sec.i.e speed of player is 1m/s so The distance travelled is (1*(11*60)+40)=700m i.e 3.5 rounds of the field so displacement is AC(see in photo)=diagonal of square According to pythagorus theorem. (AD)^2+(DC)^2=(AC)^2. So AC=(2500+2500)^1/2. AC=50root2ANSWER:option D