Question

A player moves along the boundary of a square ground of side 50m in 200sec. The magnitude of displacement of the player at the end of 11 minutes 40seconds from his initial position is

(a) 50m

(b) 150m

(c) 200m

(d) 50√2

Answer 1

Explanation:

player completes one round in 200 sec

convert the given time into seconds

11min= 11 * 60= 660 ( 1 min is 60 seconds)

660+40=700 sec

time is 700 seconds

at the end of 600 seconds player completed 3 rounds..

as per the diagram i gave he is at c.

find ac using pythagoras theorem

u will arrive at the answer (d).