a player stops a ball of mass 200 gram moving towards him with velocity 20 metre per second if the ball remains in correct with players for 0.1 second find impulse and average resistive force on the ball
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As F=ma
a=-20/0.1
a=-200ms‐².
F=.2×-200 N
F=-40N.
SO , Average resistive force is 40N.
Impulse = F×time
Impulse =40×0.1 NS
Impulse =4Ns.
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