A player takes 0 1s in catching a ball of mass 150g moving with a velocity of 30m/s. The force imparted by the ball on the hands of the player is
Answers
so the answer of this question is 45N
Answer :
›»› The force imparted by the ball on the hands of the player is -45 Newton (N).
Given :
- A player takes 1 s in catching a ball of mass 150g moving with a velocity of 30m/s.
To Calculate :
- The force imparted by the ball on the hands of the player = ?
How to calculate?
Here in this question we have to calculate the force imparted by the ball on the hands of the player. So, firstly we need to convert the unit of mass gram to kilogram, after that we need to calculate the acceleration produced or acceleration of a player, after all this we will calculate the force imparted by the ball on the hands of the player on the basis of conditions given above.
To convert the unit of mass of the ball from gram to kilogram, we will divide the mass value by 1000
Since we are provided with time taken, initial velocity, we will use the first equation of motion to calculate the acceleration produced or acceleration of the player.
But according to the given information ball moving with a velocity 30 m/s after that ball come to test.
Here we can conclude that:
→ Final velocity will be 0 m/s.
To calculate the force imparted by the ball on the hands of the player we will use the second law of Newton to calculate the force imparted by the ball on the hands of the player.
Calculations :
Converting unit of mass from gram to kilogram:
==> Mass = 150 gram.
==> Mass = 150 ÷ 1000
==> Mass = 0.15 kg.
Calculating acceleration produced or acceleration of the player:
From first equation of motion
⇒ v = u + at
⇒ 0 = 30 + a × 0.1
⇒ 0 = 30 + 0.1a
⇒ 0 - 30 = 0.1a
⇒ -30 = 0.1a
⇒ a = -30/0.1
⇒ a = -300
Now,
Calculating force imparted by the ball on the hands of the player:
From second law of Newton
⇒ F = ma
⇒ F = 0.15 × (-300)
⇒ F = -45